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x^2-4x+3=2x-11
We move all terms to the left:
x^2-4x+3-(2x-11)=0
We get rid of parentheses
x^2-4x-2x+11+3=0
We add all the numbers together, and all the variables
x^2-6x+14=0
a = 1; b = -6; c = +14;
Δ = b2-4ac
Δ = -62-4·1·14
Δ = -20
Delta is less than zero, so there is no solution for the equation
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